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mixing remains: eliminating the complement contributes O(r8)O(r^8) for fixed positive phase edges and O(r6)O(r^6) for zero edges, both smaller than the displayed term. Uniformity holds on bounded aa sets at fixed carrier and coefficients, not through a vanishing positive edge gap or an infinite carrier limit. At N=1N=1, a tilt along the parallel covariance axis gives separate coefficients Bj+∣a∣2AjB_j+|a|^2 A_j, with B∥/A∥=16(d+1)2B_\parallel/A_\parallel=16(d+1)^2 and B⊥/A⊥=16(d+1)(d+2)B_\perp/A_\perp=16(d+1)(d+2). This is a wavelength-dependent disturbance crossover, not a particle encounter acceptance angle. There is no unused direction at depth ten. The principal directional-crossover.md and independent 112-check review establish this limit.

Finite Replacement Fractions And Charge Costs

The small-tail comparison does not decide the cost of replacing a finite fraction of a pattern. A two-region algebraic control separates that question from the smooth-wall problem. Give the high and lower uniform prefixes background weights 1−t,t1-t,t, keep n=ρn=\rho, and initially omit their joining layer. Let DH,DLD_H,D_L be their counts, Δ=mH−mL>0\Delta=m_H-m_L>0, and

AN=N(N+d+1)(d+1)2(d+2),B=d(NH−NL)2(d+1)2. A_N=\frac{N(N+d+1)}{(d+1)^2(d+2)},\qquad B=\frac{d(N_H-N_L)^2}{(d+1)^2}.

At fixed occupations, the phase-compensation Gram matrix is the integral of the local covariance. It is not the covariance of the spatially averaged occupations. The exact minimum horizontal kinetic energies per QQ are

Cpair(t)=t2(DH/DL−1)2ϵ(1−t),Caffine(t)=t2B2ϵ[(1−t)AH+tAL]. \mathcal C_{\rm pair}(t)= \frac{t^2(D_H/D_L-1)}{2\epsilon(1-t)},\qquad \mathcal C_{\rm affine}(t)= \frac{t^2B}{2\epsilon[(1-t)A_H+tA_L]}.

For independent pair phases, complete proper-prefix replacement cannot preserve the deleted pair charges: their canonical pairing vanishes when the pair amplitude is exactly zero. The displayed cost diverges as t→1t\to1. For affine charges, the endpoint cost is finite if NL>0N_L>0; the origin NL=0N_L=0 has a singular covariance and cannot restore the nonzero deficit. These statements distinguish the two phase-edge choices.

Put s=2ϵΔs=2\epsilon\Delta and R=DH/DL−1R=D_H/D_L-1. The bulk energy −Δt+C(t)-\Delta t+\mathcal C(t) is negative precisely for positive tt below

tpair=sR+s,taffine=sAHB+s(AH−AL). t_{\rm pair}=\frac{s}{R+s},\qquad t_{\rm affine}=\frac{sA_H}{B+s(A_H-A_L)}.

The affine threshold can exceed one. On the flattened positive-prefix law, xd=2ϵμdx_d=2\epsilon\mu_d gives tpair=xdDL/(1+xdDL)t_{\rm pair}=x_dD_L/(1+x_dD_L), independent of NHN_H. For a zero prefix use the actual shared origin clock μ3\mu_3; the same-depth simplification applies only when its clock really equals that sector unit. These sharp-region formulas are not admissible finite-gradient spatial preparations or universal bounds on smooth walls. A wall changes both the deficit and the covariance.

There is a separate smooth full-space endpoint for positive phase edges and NL>0N_L>0. Use the centered lower texture everywhere, retain the rational support, and add K=HLCov⁡L−1(qH−qL)/ϵK=H_L\operatorname{Cov}_L^{-1}(q_H-q_L)/\epsilon. Then et=mLJeL+Ke_t=m_LJe_L+K preserves QQ and the original affine charges. It carries momentum p=Q(qH−qL)/ℓp=Q(q_H-q_L)/\ell, which the scalar support velocity Wt=−(p/g)⋅∇WW_t=-(p/g)\cdot\nabla W cancels, with g=Qωmin⁡/159g=Q\omega_{\min}/159. Radial symmetry makes the integrated carrier angular moment zero, and scalar recoil has zero angular density. The complete endpoint energy is

EendQ=mL+B2ϵAL+159B2ωmin⁡ℓ2. \frac{E_{\rm end}}Q=m_L+\frac{B}{2\epsilon A_L} +\frac{159B}{2\omega_{\min}\ell^2}.

It is lower than the high branch exactly when the two positive costs sum to less than Δ\Delta. Equality and the reversed inequality are retained; the unresolved physical ℓ\ell has not been fitted to force success. With ϵ=ωmin⁡ℓ2/(4M2)\epsilon=\omega_{\min}\ell^2/(4M^2) the condition becomes

xd>BDH−DL(1AL+1594M2). x_d>\frac{B}{D_H-D_L} \left(\frac1{A_L}+\frac{159}{4M^2}\right).

This finite-energy endpoint is not close to the high branch pointwise at infinity, is not a stationary compensated particle, and supplies no connecting trajectory. Both entropy prescriptions give the same initial energy because n=ρn=\rho; their evolution need not agree. The source finite-fraction-phase-cost/report.md has 4220 author checks and an independent 483-check review, including eleven maintained same-depth pairs and thirteen positive-prefix controls. No second tau, integer bottom assignment or photon mass branch is introduced.

Density Redistribution At Fixed Total Charge

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