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Summary: Research record, section 83: Reciprocity audit: Hermiticity does not force observed-unobserved exchange symmetry.

Provenance

Preserved from interaction notebook section 83, recorded 2026-09-05 and corrected 2026-09-06. Original sequence contents. This is an exploratory research record, not an independently established V2 result. Read the related later audits before using an intermediate conclusion.

83. Reciprocity audit: Hermiticity does not force observed-unobserved exchange symmetry

Section 82 found that an exact factor-swap symmetry on

4=(2O,2H) \mathbf4=(\mathbf2_O,\mathbf2_H)

would select

q=1. q=1.

The next question is whether that symmetry already follows from the reciprocal/Hermitian character of the scattering lock or the projected cross-depth interaction.

It does not.

83.1 Hermiticity and factor exchange are different conditions

In the aligned frame, the ideal quadratic lock Hessian is

Klock=κ(I−I−II). K_{\rm lock} =\kappa \begin{pmatrix} I&-I\\ -I&I \end{pmatrix}.

Define the observed-unobserved exchange involution

SOH=(0II0). S_{OH} =\begin{pmatrix} 0&I\\ I&0 \end{pmatrix}.

For this special equal-diagonal lock,

[Klock,SOH]=0. [K_{\rm lock},S_{OH}]=0.

So the particular Procrustes Hessian used in sections 56--57 is exchange symmetric after alignment.

However, the most general reciprocal Hermitian block with the same off-diagonal link is

Kgen=(aI−κI−κIcI). K_{\rm gen} =\begin{pmatrix} aI&-\kappa I\\ -\kappa I&cI \end{pmatrix}.

It is Hermitian for arbitrary real

a, c, κ, a,\ c,\ \kappa,

but

[SOH,Kgen]=0 [S_{OH},K_{\rm gen}]=0

if and only if

a=c. \boxed{a=c.}

Therefore

Hermiticity / reciprocal response does not imply O↔H exchange symmetry. \boxed{\text{Hermiticity / reciprocal response does not imply }O\leftrightarrow H\text{ exchange symmetry}.}

The exchange symmetry of the special lock Hessian comes from the additional choice of equal observed and unobserved self-stiffnesses, not from self-adjointness alone.

83.2 The orbit generator makes the distinction especially clear

The spinor orbit family is

G~q=diag⁡(q+14,−q+14,−34,14). \widetilde G_q =\operatorname{diag} \left( q+\frac14, -q+\frac14, -\frac34, \frac14 \right).

It is Hermitian for every real qq.

The spin-factor swap acts by

∣+−⟩↔∣−+⟩. |+-\rangle\leftrightarrow|-+\rangle.

Direct calculation gives

[SOH,G~q]=0 [S_{OH},\widetilde G_q]=0

if and only if

q=1. \boxed{q=1.}

Hence the desired q=1q=1 value is selected by exchange invariance, not by Hermiticity.

83.3 The locked complex structure is not itself exchange-even

In the aligned real 3+33+3 frame, the locked complex structure is

Jlock=(0I−I0). J_{\rm lock} =\begin{pmatrix} 0&I\\ -I&0 \end{pmatrix}.

With the same exchange involution

SOH=(0II0), S_{OH} =\begin{pmatrix} 0&I\\ I&0 \end{pmatrix},

one finds

{SOH,Jlock}=0, \boxed{\{S_{OH},J_{\rm lock}\}=0,}

not

[SOH,Jlock]=0. [S_{OH},J_{\rm lock}]=0.

So exchanging the two locked three-planes reverses the sign of the complex structure:

SOHJlockSOH−1=−Jlock. S_{OH}J_{\rm lock}S_{OH}^{-1}=-J_{\rm lock}.

This is important conceptually. The frame lock identifies the two three-frames, but it does not automatically make them indistinguishable under an ordinary commuting symmetry. The complex orientation distinguishes the direction of the map

H→O H\to O

from its reverse.

83.4 The nucleus also distinguishes the two halves

The bound-state module defines

O O

as the nuclear-relative three-plane and

H=O⊥ H=O^\perp

as its orthogonal complement. The construction therefore gives the two subspaces different physical roles before locking.

This means an O↔HO\leftrightarrow H symmetry cannot be inferred merely from their equal dimension.

83.5 Status of the exchange selection route

The exact result from section 82 remains true:

O↔H invariance of Gq⟹q=1. O\leftrightarrow H\text{ invariance of }G_q \Longrightarrow q=1.

But section 83 shows that current V2 does not derive that invariance from:

  • self-adjointness of the master Dirac operator;
  • reciprocal cross-depth response;
  • Hermiticity of the lock Hessian;
  • or the existence of the locked complex structure.

The exchange route is therefore conditional and cannot yet be used as a first-principles derivation of the 1:1:31{:}1{:}3 orbit spectrum.

83.6 Revised proof obligation

The integer orbit parameter remains open unless one can derive an additional symmetry or selection law. The remaining possibilities are now sharply separated:

  1. derive a genuine O↔HO\leftrightarrow H invariance of the stationary Hamiltonian circle from the projected electron interaction;
  2. derive q=1q=1 from a different representation-theoretic property of the selected circle;
  3. derive a dynamical variational rule over the allowed integral circles;
  4. or accept qq as presently undetermined in the written V2 action.

The next useful test is representation-theoretic rather than variational: classify the integral U(1)U(1) subgroups of SU(4)SU(4) compatible with the locked subgroup and the required 1⊕3\mathbf1\oplus\mathbf3 decomposition, and ask whether regularity, primitiveness, or isotropy of the locked orbit reduces the family (q,−q,−1,0)(q,-q,-1,0) to q=1q=1 without invoking factor exchange.